Atom oscillation frequency determines photon frequency

The Forces of Nature by Kelland Terry, Ph.D.

As explained in the previous blog, the atom’s electrons and quarks have the same string cycle frequency because the two subatomic particles are connected by elastic strings.

The oscillation frequency of the photons emitted by atoms during photon emission increases if the atom’s frequency of oscillation is raised. This means atoms not only emit visible light, as previously discussed, but other photons as well depending on the oscillation frequency of the atom. This makes it possible for a radio station transmitting antenna to emit radio wave photons with different frequencies. This is accomplished by controlling the oscillation frequency of the atoms with an electric current.

We might imagine that a quark spinning on its axis assimilates some of the proton’s elastic goo, which becomes available to be ejected as a photon. Ejection only takes place when the velocity of the quark is suddenly accelerated, which in turn rapidly increases its spin angular momentum. The faster the acceleration, the larger the mass ejected as a photon.

As explained previous, the photon ejected by a quark is captured by an electron in orbit about the proton. The electron moves to an outer orbit because of an increase in spin angular momentum. This is an unstable state and the electron emits this photon or one of less mass and moves to an inner orbit. In the case of the radio wave transmitter oscillating at low frequency, the photon emitted is a small radio wave.

It is likely that ejection takes place shortly after the beginning of the string cycle when the goo inside the quark is at its densest state and a new string cycle is commencing. At this point in time the conserved potential energy in the condensed goo is greatest.

Max Planck’s constant

The Forces of Nature by Kelland Terry, Ph.D.

I have already introduced the idea that the oscillation frequency of a gamma ray photon is much greater than a small radio wave photon. Oscillation frequency is directly related to the energy of the photon. What we are really saying is that the rate a photon goes through its string cycles is directly related to the photon’s mass and energy.

In 1900, Max Planck compared oscillation frequency and the energy of light, and from this he was able to show that the energy of a photon can be calculated using its frequency: E = hf, which applies to all photons. The letter h in this equation is Planck’s constant and f is the frequency of oscillation. Planck’s constant has a value of 6.626 x 10^-34 joule seconds. Thus, the energy in joules for a radio wave with a frequency of 1 x 10^4 is 6.626 x 10^-30 joules. The energy of a photon of visible light with a frequency of 1 x 10^15 is 6.626 x 10^-19 joules.

Planck came to this conclusion: The total energy of a given source of light is equal to nfh, where n is the number of photons emitted, f is the frequency of the photons, and h is Planck’s constant. This was an important contribution by Planck because it clearly stated that light was composed of discrete particles whose frequency and number dictated the total energy of the light emitted.

We still have Einstein and the special theory of relativity to be concerned with but we’ll get there eventually. Till then be safe and in good health. Kelland—www.vestheory.com