In the previous blog, we saw how the speed of light is equal to magnitude of the photon’s electric field divided by the magnitude of the photon’s magnetic field.
The electric field E is proportional to the lines of electric force, which according to elastic string theory is proportional to the number of electons creating this field. In the same manner, the magnetic field B is proportional to the lines of magnetic force, which is proportional to the number of magnons creating this field. This leads to the conclusion that the number of electons emanating from a photon divided by the number of magnons is equal to the speed of light.
Thus,
This means there are exactly 299,792,459 electons for every magnon. I believe it is relevant that careful measurement of the speed of light shows that the number of electons is an even number when compared to magnons, just as expected if we are dealing with the number of elastic strings.
Since the energy density of the electon field is equal to the energy density of the magnon field, it must take 299,792,459 electons to equal the energy of one magnon. It is possible then that the mass of one magnon is equal to the mass of 299,792,459 electons.
In the next blog, I will review string cycles in view of this new information, and what this means for the self-induction of elastic strings. Till then be safe and in good health. Kelland—www.vestheory.com
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